Answer:
[tex]\large\boxed{\dfrac{1}{8}x-\dfrac{49}{8}=\dfrac{1}{8}(x-49)}[/tex]
Step-by-step explanation:
[tex]\dfrac{1}{8}x=\dfrac{1}{8}\cdot x\\\\\dfrac{49}{8}=\dfrac{1\cdot49}{8}=\dfrac{1}{8}\cdot49\\\\\dfrac{1}{8}x-\dfrac{49}{8}=\dfrac{1}{8}\cdot x-\dfrac{1}{8}\cdot49=\dfrac{1}{8}(x-49)[/tex]
