Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3.2}{ h},\stackrel{-2.1}{ k})\qquad \qquad radius=\stackrel{4.3}{ r}\\[2em] [x-(-3.2)]^2+[y-(-2.1)]^2=4.3^2\implies (x+3.2)^2+(y+2.1)^2=18.49[/tex]