Answer:
[tex]\boxed{y=4x^3-x^2-50x+25}[/tex]
Step-by-step explanation:
The given function is
[tex]y=(x-5)(x+5)(2x-1)[/tex]
Observe that, the first two factors are from difference of two squares.
[tex]\Rightarrow y=(x^2-5^2)(2x-1)[/tex]
[tex]\Rightarrow y=(x^2-25)(2x-1)[/tex]
We expand the brackets using the distributive property to obtain;
[tex]\Rightarrow y=2x^2(2x-1)-25(2x-1)[/tex]
[tex]\Rightarrow y=4x^3-x^2-50x+25[/tex]
The above function is now in standard form, since the terms are arranged in descending powers of [tex]x[/tex].
