beshotheboss beshotheboss
  • 25-01-2019
  • Physics
contestada

a rock thrown straight up takes 4.2 s to reach its maximum height what was its initial velocity

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JemdetNasr JemdetNasr
  • 03-02-2019

Consider the upward direction of motion as positive and downward direction of motion as negative.

a = acceleration due to gravity in downward direction = - 9.8 [tex]\frac{m }{s^{2}}[/tex]

v₀ = initial velocity of rock in upward direction = ?

v = final velocity of rock at the highest point = 0 [tex]\frac{m }{s}[/tex]

t = time to reach the maximum height = 4.2 sec

Using the kinematics equation

v = v₀ + a t

inserting the values

0 = v₀ + (- 9.8) (4.2)

v₀ = 41.2 [tex]\frac{m }{s}[/tex]


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