A 5.0 kg ball is whirled on a 1.2 m string so that the ball moves in uniform circular motion in a horizontal plane. The centripetal force is 22 N. What is the tangential speed of the ball?
Answer:
2.3 m/s
Fc=22N
m= 5.0kg
r= 1.2m
vt= √(Fc* r /m)
√(22N *1.2 / 5.0kg) = 2.3 m/s