The line crosses the x -axis at point (9,0) and the y-axis at point (0,6).
If the equation of the line is [tex]y=kx+b,[/tex] then substitute the coordinates of the points into this equation:
1) [tex]0=9k+b;[/tex]
2) [tex]6=b.[/tex]
Substitute the second equation into the first:
[tex]9k+6=0,\\ \\k=-\dfrac{2}{3}.[/tex]
The equation of the line is
[tex]y=-\dfrac{2}{3}x+6.[/tex]
Answer: option C
