Answer:
Given: A parallelogram EFGH in which diagonals intersect at point J.
To Find: A segment congruent to EJ.
Solution: In parallelogram EFGH
Point of intersection of Diagonals EG and FH are point J.
As we know diagonals of parallelogram bisect each other.
So, EJ=JG and FJ=JH
∵ Solution is EJ≅ JG
