Note how 2x^2 is a common factor of these three terms. Thus,
8x^5 + 2x^4 + 4x^2 = (2x^2)(4x^3 + x^2 + 2)
The latter factor, a cubing equation, does not have any integer roots.
Answer: Factorisation of the above expression is given by
[tex]2x^2(4x^3+x^2+2)[/tex]
Step-by-step explanation:
Since we have given that
[tex]8x^5 + 2x^4 + 4x^2.[/tex]
We need to factorise the above expression:
[tex]8x^5 + 2x^4 + 4x^2.\\\\=2x^2(4x^3+x^2+2)[/tex]
Hence, factorisation of the above expression is given by
[tex]2x^2(4x^3+x^2+2)[/tex]
