the equation of the following line (0,0) and (10,-2)
First we find slope of the line using the given points (0,0) and (10,-2)
[tex]slope = \frac{y_2-y_1}{x_2-x_1}[/tex]
(0,0) is (x1,y1) and (10,-2) is (x2,y2)
[tex]slope = \frac{-2-0}{10-0}[/tex] = [tex]\frac{-1}{5}[/tex]
Now we use equation y=mx+b
where m is the slope and b is the y intercept
[tex]y=\frac{-1}{5} x +b[/tex]
Plug in (0,0) and solve for b
[tex]0=\frac{-1}{5}(0) +b[/tex]
b=0
So equation of the line is [tex]y=\frac{-1}{5}x[/tex]
