g(x) = x²
a) To find g(1) substitute with x = 1 at the function g(x)
∴ g(1) = 1² = 1
b) substitute with x = -2 at the function g(x)
∴ g(-2) = (-2)² = 4
c) substitute with x = -x at the function g(x)
∴ g(-x) = (-x)² = x²
d) substitute with x = 2y at the function g(x)
∴ g(2y) = (2y)² = 4y²
e) substitute with x = 2+h at the function g(x)
∴ g(2+h) = (2+h)² = h² + 4h + 4
