Find the particular solution to t².y′′−t(5t−2)y′−(5t−2)y=2t³ , t>0, y₁(t)=t, y₂(t)=te⁵ᵗ
a) yₚ(t)=t³
a) yₚ(t)=2t³
a) yₚ(t)=t²
a) yₚ(t)=3t³