tamaragip3319 tamaragip3319

25-05-2023
Mathematics

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In the geometric series [infinity]Σn= 2^n/(-5)^n+1
we have r=_
Since |r|< _
Then [infinity]Σn= 2^n/(-5)^n+1 converges and [infinity]Σn= 2^n/(-5)^n+1 _/_

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